Write in Exponential Form -3 = log base 2 of 1/8

$- 3 = \log_{2} (\frac{1}{8})$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 2$ , $x = \frac{1}{8}$ , and $y = - 3$ .

$b = 2$

$x = \frac{1}{8}$

$y = - 3$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$2^{- 3} = \frac{1}{8}$

Write in Exponential Form -3 = log base 2 of 1/8

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