Solve for x fourth root of x=2

$\sqrt[4]{x} = 2$

To remove the radical on the left side of the equation, raise both sides of the equation to the power of $4$ .

${\sqrt[4]{x}}^{4} = 2^{4}$

Simplify each side of the equation.

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Multiply the exponents in ${(x^{\frac{1}{4}})}^{4}$ .

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Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{4} \cdot 4} = 2^{4}$

Cancel the common factor of $4$ .

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Cancel the common factor.

$x^{\frac{1}{4} \cdot 4} = 2^{4}$

Rewrite the expression.

$x^{1} = 2^{4}$

Simplify.

$x = 2^{4}$

Raise $2$ to the power of $4$ .

$x = 16$

Solve for x fourth root of x=2

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