Solve by Substitution -x-3y=9 , x+3y=9

$- x - 3 y = 9$ , $x + 3 y = 9$

Subtract $3 y$ from both sides of the equation.

$x = 9 - 3 y$

$- x - 3 y = 9$

Replace all occurrences of $x$ with $9 - 3 y$ in each equation.

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Replace all occurrences of $x$ in $- x - 3 y = 9$ with $9 - 3 y$ .

$- (9 - 3 y) - 3 y = 9$

$x = 9 - 3 y$

Simplify $- (9 - 3 y) - 3 y$ .

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Simplify each term.

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Apply the distributive property.

$- 1 \cdot 9 - (- 3 y) - 3 y = 9$

$x = 9 - 3 y$

Multiply $- 1$ by $9$ .

$- 9 - (- 3 y) - 3 y = 9$

$x = 9 - 3 y$

Multiply $- 3$ by $- 1$ .

$- 9 + 3 y - 3 y = 9$

$x = 9 - 3 y$

$- 9 + 3 y - 3 y = 9$

$x = 9 - 3 y$

Combine the opposite terms in $- 9 + 3 y - 3 y$ .

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Subtract $3 y$ from $3 y$ .

$- 9 + 0 = 9$

$x = 9 - 3 y$

Add $- 9$ and $0$ .

$- 9 = 9$

$x = 9 - 3 y$

$- 9 = 9$

$x = 9 - 3 y$

$- 9 = 9$

$x = 9 - 3 y$

$- 9 = 9$

$x = 9 - 3 y$

Since $- 9 = 9$ is not true, there is no solution.

No solution

Solve by Substitution -x-3y=9 , x+3y=9

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