Simplify (y^2-9)/(-2y)*(-5y)/(y+3)

$\frac{y^{2} - 9}{- 2 y} \cdot \frac{- 5 y}{y + 3}$

Simplify the numerator.

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Rewrite $9$ as $3^{2}$ .

$\frac{y^{2} - 3^{2}}{- 2 y} \cdot \frac{- 5 y}{y + 3}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = y$ and $b = 3$ .

$\frac{(y + 3) (y - 3)}{- 2 y} \cdot \frac{- 5 y}{y + 3}$

Simplify terms.

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Cancel the common factor of $y + 3$ .

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Cancel the common factor.

$\frac{(y + 3) (y - 3)}{- 2 y} \cdot \frac{- 5 y}{y + 3}$

Rewrite the expression.

$\frac{y - 3}{- 2 y} \cdot (- 5 y)$

Cancel the common factor of $y$ .

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Factor $y$ out of $- 2 y$ .

$\frac{y - 3}{y \cdot - 2} \cdot (- 5 y)$

Factor $y$ out of $- 5 y$ .

$\frac{y - 3}{y \cdot - 2} \cdot (y \cdot - 5)$

Cancel the common factor.

$\frac{y - 3}{y \cdot - 2} \cdot (y \cdot - 5)$

Rewrite the expression.

$\frac{y - 3}{- 2} \cdot - 5$

Combine $\frac{y - 3}{- 2}$ and $- 5$ .

$\frac{(y - 3) \cdot - 5}{- 2}$

Move $- 5$ to the left of $y - 3$ .

$\frac{- 5 \cdot (y - 3)}{- 2}$

Dividing two negative values results in a positive value.

$\frac{5 (y - 3)}{2}$

Simplify (y^2-9)/(-2y)*(-5y)/(y+3)

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