Find Where Undefined/Discontinuous (x^2-8)/(x+40)

$\frac{x^{2} - 8}{x + 40}$

Set the denominator in $\frac{x^{2} - 8}{x + 40}$ equal to $0$ to find where the expression is undefined.

$x + 40 = 0$

Subtract $40$ from both sides of the equation.

$x = - 40$

The equation is undefined where the denominator equals $0$ , the argument of a square root is less than $0$ , or the argument of a logarithm is less than or equal to $0$ .

$x = - 40$

Find Where Undefined/Discontinuous (x^2-8)/(x+40)

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