Find Three Ordered Pair Solutions 2x-y=14

$2 x - y = 14$

Solve the equation for $y$ .

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Subtract $2 x$ from both sides of the equation.

$- y = 14 - 2 x$

Multiply each term in $- y = 14 - 2 x$ by $- 1$

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Multiply each term in $- y = 14 - 2 x$ by $- 1$ .

$(- y) \cdot - 1 = 14 \cdot - 1 + (- 2 x) \cdot - 1$

Multiply $(- y) \cdot - 1$ .

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Multiply $- 1$ by $- 1$ .

$1 y = 14 \cdot - 1 + (- 2 x) \cdot - 1$

Multiply $y$ by $1$ .

$y = 14 \cdot - 1 + (- 2 x) \cdot - 1$

Simplify each term.

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Multiply $14$ by $- 1$ .

$y = - 14 + (- 2 x) \cdot - 1$

Multiply $- 1$ by $- 2$ .

$y = - 14 + 2 x$

Choose any value for $x$ that is in the domain to plug into the equation.

Choose $0$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = - 14 + 2 (0)$

Simplify $- 14 + 2 (0)$ .

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Multiply $2$ by $0$ .

$y = - 14 + 0$

Add $- 14$ and $0$ .

$y = - 14$

Use the $x$ and $y$ values to form the ordered pair.

$(0, - 14)$

Choose $1$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = - 14 + 2 (1)$

Simplify $- 14 + 2 (1)$ .

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Multiply $2$ by $1$ .

$y = - 14 + 2$

Add $- 14$ and $2$ .

$y = - 12$

Use the $x$ and $y$ values to form the ordered pair.

$(1, - 12)$

Choose $2$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = - 14 + 2 (2)$

Simplify $- 14 + 2 (2)$ .

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Multiply $2$ by $2$ .

$y = - 14 + 4$

Add $- 14$ and $4$ .

$y = - 10$

Use the $x$ and $y$ values to form the ordered pair.

$(2, - 10)$

These are three possible solutions to the equation.

$(0, - 14), (1, - 12), (2, - 10)$

Find Three Ordered Pair Solutions 2x-y=14

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