Find the Vertex y=-(x-3)^2-1

$y = - {(x - 3)}^{2} - 1$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - 1$

$h = 3$

$k = - 1$

Find the vertex $(h, k)$ .

$(3, - 1)$

Find the Vertex y=-(x-3)^2-1

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