Find the Standard Form of the Parabola x^2+2x-12y+73=0

$x^{2} + 2 x - 12 y + 73 = 0$

Move all terms not containing $y$ to the right side of the equation.

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Subtract $x^{2}$ from both sides of the equation.

$2 x - 12 y + 73 = - x^{2}$

Subtract $2 x$ from both sides of the equation.

$- 12 y + 73 = - x^{2} - 2 x$

Subtract $73$ from both sides of the equation.

$- 12 y = - x^{2} - 2 x - 73$

Divide each term by $- 12$ and simplify.

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Divide each term in $- 12 y = - x^{2} - 2 x - 73$ by $- 12$ .

$\frac{- 12 y}{- 12} = \frac{- x^{2}}{- 12} + \frac{- 2 x}{- 12} + \frac{- 73}{- 12}$

Cancel the common factor of $- 12$ .

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Cancel the common factor.

$\frac{- 12 y}{- 12} = \frac{- x^{2}}{- 12} + \frac{- 2 x}{- 12} + \frac{- 73}{- 12}$

Divide $y$ by $1$ .

$y = \frac{- x^{2}}{- 12} + \frac{- 2 x}{- 12} + \frac{- 73}{- 12}$

Simplify each term.

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Dividing two negative values results in a positive value.

$y = \frac{x^{2}}{12} + \frac{- 2 x}{- 12} + \frac{- 73}{- 12}$

Cancel the common factor of $- 2$ and $- 12$ .

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Factor $- 2$ out of $- 2 x$ .

$y = \frac{x^{2}}{12} + \frac{- 2 (x)}{- 12} + \frac{- 73}{- 12}$

Cancel the common factors.

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Factor $- 2$ out of $- 12$ .

$y = \frac{x^{2}}{12} + \frac{- 2 (x)}{- 2 (6)} + \frac{- 73}{- 12}$

Cancel the common factor.

$y = \frac{x^{2}}{12} + \frac{- 2 x}{- 2 \cdot 6} + \frac{- 73}{- 12}$

Rewrite the expression.

$y = \frac{x^{2}}{12} + \frac{x}{6} + \frac{- 73}{- 12}$

Dividing two negative values results in a positive value.

$y = \frac{x^{2}}{12} + \frac{x}{6} + \frac{73}{12}$

Find the Standard Form of the Parabola x^2+2x-12y+73=0

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