Find the Slope of a Perpendicular Line y=5/7x+2

$y = \frac{5}{7} x + 2$

Rewrite in slope-intercept form.

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The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Combine $\frac{5}{7}$ and $x$ .

$y = \frac{5 x}{7} + 2$

Rewrite in slope-intercept form.

$y = \frac{5}{7} x + 2$

Using the slope-intercept form, the slope is $\frac{5}{7}$ .

$m = \frac{5}{7}$

The equation of a perpendicular line to $y = \frac{5 x}{7} + 2$ must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{\frac{5}{7}}$

Simplify the result.

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Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = - (1 (\frac{7}{5}))$

Multiply $\frac{7}{5}$ by $1$ .

$m_{perpendicular} = - \frac{7}{5}$

Find the Slope of a Perpendicular Line y=5/7x+2

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